Day 13

Today we reviewed:
- The parts of animal and plant cells
- How DNA contains information and forms patterns in base pairs
- What mutations are, and how there are different kinds of mutations
-That mutations can be positive, negative, or neutral.

Today's Homework is:
Pg 130 # 1 - 5
Pg 135 # 1 - 6
Chapter review Pg 146# 1 - 21

Also, students will be preparing for the Unit 3 test on Electricity for Thursday. You will be permitted 1 single sided sheet of paper to take into the test and use as a cheat sheet.

For Friday's chapter 4 quiz on cells - all the "Matching Answers" are on page 122-124. Most of them were covered in the homework on page 124 # 1-7 which we just handed in.

Yesterday's Work:

Pg 330 # 1 - 21
1. A series circuit contains only one pathway,
whereas a parallel circuit contains more than
one pathway.

2. The current through the second resistor is the
same as the current through the first resistor.

3. The total voltage lost on the three resistors
would be 6.0 V.

4. (a) Increases
(b) Decreases

5. The voltage is the same on both of the
resistors.
TR 3-50 MHR • Characteristics of Electricity

6. (a) The total current leaving the junction
point must equal the current entering the
junction point.
(b) The current in the two pathways will be
different.

7. (a) Power is the rate at which energy is transformed.
(b) Power is measured in watts (W).

8. Power is the product of voltage and current:
P = VI.

9. (a) Electrical energy is measured in joules (J)
and kilowatt-hours (kW•h).
(b) The kilowatt-hour is a larger unit.

10. Energy is the product of power and time:
E = Pt.


11. (a) The second bulb goes out.
(b) The result would be different if the bulbs
were connected in parallel. Even if one
bulb “burns out,” there is still a pathway
for current through the second bulb and
therefore it would stay lit.

12. (a) Students’ answers may vary but could
include a car racetrack or a single-lane
bridge.
(b) Students’ answers may vary but could
include multiple checkouts at the supermarket
or entering a bus by two different
doors.

13. (a) The resistors are connected in parallel.
Electrons leaving the battery have two
pathways to return to the battery.
(b) The resistors are connected in series.
Electrons leaving the battery must travel
through both resistors in order to return to
the battery.
14. V1 = 5.0 V, A1 = 2.0 A
15. (a) The current would decrease because
adding another resistor in series increases
the total resistance of the circuit.
(b) The current would increase because adding
another resistor in parallel decreases the
total resistance of the circuit.
16. V1 = 6.0 V, A1 = 2.0 A
17. 144 W
18. 10 A
19. 18 W
20. Lamp 1 = 27 W, Lamp 2 = 18 W
21. Light bulb, hair dryer, microwave oven

BLM 3-23, Practising Calculating Resistance
1. R = 3600 Ω or 3.6 × 103 Ω
2. I = 0.48 A or 4.8 × 10-1 A
3. V = 9.0 V
4. I = 18.3 A or 1.83 × 10-1 A
5. 3.0 Ω
6. 11 Ω
7. 220 Ω or 2.20 × 102 Ω
8. 0.30 A or 3.0 × 10-1 A
9. 4 × 10-4 A 0.0004 A or 0.04 A or 0.04 mA
10. 120 V or 1.20 × 102 V

BLM 3-28, Series Circuits
1. only one
2. equal to
3. different from
4. increases
5. equal to
6. Voltage = 10 V, current = 3.0 A
7. Voltage = 12 V, current = 4.0 A


BLM 3-29, Parallel Circuits
1. more than one
2. different from
3. equal to
4. decreases
5. equal to
6. Voltage = 12 V, current = 6.0 A
7. Voltage = 90 V, current = 1.0 A